59. Spiral Matrix II

59. Spiral Matrix II

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.

For example,
Given n = 3,
You should return the following matrix:

[
 [ 1, 2, 3 ],
 [ 8, 9, 4 ],
 [ 7, 6, 5 ]
]

题意:

  给定一个整数n,生成一个以1到n的平方根为螺旋顺序元素的螺旋矩阵。

思路:

  主要参照54. Spiral Matrix方法二。

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class Solution {
public:
vector<vector<int>> generateMatrix(int n) {
vector<vector<int>> res(n,vector<int>(n, 0));
int l = 0, r = n - 1, u = 0, d = n - 1, k = 1;
while (1)
{
//up
for (int col = l;col<=r;col++)
{
res[u][col] = k++;
}
if (++u>d) break;
//right
for (int row = u; row <= d; row++)
{
res[row][r] = k++;
}
if (--r < l) break;
//down
for (int col = r; col >= l; col--)
{
res[d][col] = k++;
}
if (--d < u) break;
//left
for (int row = d; row >= u; row--)
{
res[row][l] = k++;
}
if (++l > r) break;
}
return res;
}
};

 Java Code

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class Solution {
public int[][] generateMatrix(int n) {
if (n == 0) {
return new int[0][0];
}

int[][] res = new int[n][n];
int left = 0;
int right = n - 1;
int up = 0;
int down = n - 1;
int element = 1;

while (true) {
for (int col = left; col <= right;col++) {
res[up][col] = element++;
}
up++;
if (up > down) {
break;
}


for (int row = up; row <= down;row++) {
res[row][right] = element++;
}
right--;
if (right < left) {
break;
}


for (int col = right; col >= left;col--) {
res[down][col] = element++;
}
down--;
if (down < up) {
break;
}


for (int row = down; row >= up;row--) {
res[row][left] = element++;
}
left++;
if (left > right) {
break;
}
}

return res;
}
}